Fred Anapol Forensic Consultant is categorized under Business Consultants in Milwaukee, WI and active since 2010.
Fred Anapol Forensic Consultant was established in 2010, and today employs 1 to 4, earning $50.000 to $99.999 per year. This is a Business Consultants business, which does work in the B2B market, and is classified as a Business Consultants, under code number 541618 by the NAICS.
If you are seeking more information, feel free to contact Fred Anapol at the company’s single location by writing to 2201 East Newton Avenue, Milwaukee, Wisconsin WI 53211 or by phoning (414) 963-4989. You can also visit this business on Facebook by going to their profile page at Facebook or on find them on Twitter.
| Business Name: | Fred Anapol Forensic Consultant |
| Contact Person: | Fred Anapol |
| Address: | 2201 East Newton Avenue, Milwaukee, Wisconsin 53211 |
| Phone Number: | (414) 963-4989 |
| Annual Revenue (USD): | $50.000 to $99.999 |
| Founded: | 2010 |
| Location Type: | Single Location |
| Employee Number: | 1 to 4 |
| Business Type: | B2B (Business to Business) |
| Business Category: | Business Consultants |
| SIC Code: | 8748 |
| NAICS Code: | 541618 |
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Fred Anapol Forensic Consultant was started in 2010 to provide professional Business Consultants under the SIC code 8748 and NAICS code 541618. Since its inception, the company has gone on to take a total of 1 to 4 personnel under its employment and has achieved earnings of $50.000 to $99.999 per annum.
Feel free to contact Fred Anapol for inquiries that concern Fred Anapol Forensic Consultant by calling the company number (414) 963-4989, as your correspondence is most welcome. Additionally, the physical location of the single location of Fred Anapol Forensic Consultant can be found at the coordinates 43.084902,-87.882415 as well as the street address 2201 East Newton Avenue in Milwaukee, Wisconsin 53211.
For its online presence, you may visit Fred Anapol Forensic Consultant’s website at and engage with its social media outlets through on Twitter and on Facebook.