A Luchow is categorized under Family Practice Doctors in Tenafly, NJ and active since 2010.
A Luchow was established in 2010, and today employs 1 to 4, earning $100.000 to $499.999 per year. This is a Family Practice Doctors business, which does work in the B2C market, and is classified as a Family Practice Doctors, under code number 621111 by the NAICS.
If you are seeking more information, feel free to contact Anya Luchow Liberman at the company’s single location by writing to 111 East Clinton Avenue, Tenafly, New Jersey NJ 07670 or by phoning (201) 569-4585. You can also visit this business on Facebook by going to their profile page at Facebook or on find them on Twitter.
| Business Name: | A Luchow |
| Contact Person: | Anya Luchow Liberman |
| Address: | 111 East Clinton Avenue, Tenafly, New Jersey 07670 |
| Phone Number: | (201) 569-4585 |
| Annual Revenue (USD): | $100.000 to $499.999 |
| Founded: | 2010 |
| Location Type: | Single Location |
| Employee Number: | 1 to 4 |
| Business Type: | B2C (Business to Consumer) |
| Business Category: | Family Practice Doctors |
| SIC Code: | 8011 |
| NAICS Code: | 621111 |
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A Luchow was started in 2010 to provide professional Family Practice Doctors under the SIC code 8011 and NAICS code 621111. Since its inception, the company has gone on to take a total of 1 to 4 personnel under its employment and has achieved earnings of $100.000 to $499.999 per annum.
Feel free to contact Anya Luchow Liberman for inquiries that concern A Luchow by calling the company number (201) 569-4585, as your correspondence is most welcome. Additionally, the physical location of the single location of A Luchow can be found at the coordinates 40.920325,-73.958737 as well as the street address 111 East Clinton Avenue in Tenafly, New Jersey 07670.
For its online presence, you may visit A Luchow’s website at and engage with its social media outlets through on Twitter and on Facebook.