American Fidelity Assurance CO Lexington, KY - 40504

American Fidelity Assurance CO is categorized under Insurance Companies in Lexington, KY .

American Fidelity Assurance CO was established in 0, and today employs 1 to 4, earning $500.000 to $999.999 per year. This is a Insurance Companies business, which does work in the BOTH market, and is classified as a Insurance Companies, under code number 5242100 by the NAICS.

If you are seeking more information, feel free to contact Joel Mc Kenzie, President at the company’s branch by writing to 2525 Harrodsburg Road # 115, Lexington, Kentucky KY 40504 or by phoning (859) 223-8030. You can also visit this business on Facebook by going to their profile page at Facebook or on find them on Twitter.

Business Name: American Fidelity Assurance CO
Contact Person: Joel Mc Kenzie, President
Address: 2525 Harrodsburg Road # 115, Lexington, Kentucky 40504
Phone Number: (859) 223-8030
Website Address: afadvantage.com
Annual Revenue (USD): $500.000 to $999.999
Location Type: Branch
Employee Number: 1 to 4
Business Type: B2B & B2C
Business Category: Insurance Companies
SIC Code: 6411
NAICS Code: 5242100
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American Fidelity Assurance CO was started in 0 to provide professional Insurance Companies under the SIC code 6411 and NAICS code 5242100. Since its inception, the company has gone on to take a total of 1 to 4 personnel under its employment and has achieved earnings of $500.000 to $999.999 per annum.

Feel free to contact Joel Mc Kenzie, President for inquiries that concern American Fidelity Assurance CO by calling the company number (859) 223-8030, as your correspondence is most welcome. Additionally, the physical location of the branch of American Fidelity Assurance CO can be found at the coordinates 38.017243,-84.548937 as well as the street address 2525 Harrodsburg Road # 115 in Lexington, Kentucky 40504.

For its online presence, you may visit American Fidelity Assurance CO’s website at afadvantage.com and engage with its social media outlets through on Twitter and on Facebook.